Hello,
I have set a Blade HP Proliant BL460C,
I also have set Línux Debian 8.5.0 64bits.
Then I have set VMWare12.5 with a Debian 8.5.0 64bits guess.
The zcash beta 2, configuration was successfully, like it
is very well explained at:
I would like to know if:
zctestseie6wxgio.onion works when you set at
zcash.conf instead of betatestnet.z.cash.
Because the miner started two hours ago and
still my balance is 0.00000000
The number of blocks are bigger than a few
minutes ago, when I set at rpc-console the
following command:
./src/zcash-cli getinfo
I have generated the t-addr and the z-addr addresses successfully and easy.
I also know that I must set at this moment the t-addr at:
sorry I have only 2 hyperlinks, because I am newbe, reply to get the link or must read a bit.
will be written as reply: 1.1
to play with some beta coins.
Also I want to set my server Benchmark at:
sorry I have only 2 hyperlinks, because I am newbe, reply to get the link or must read a bit.
will be written as reply: 1.2
With 32 GB DDR3 1333 16cores 2.26Ghz I got when I run
zcash-cli zcbenchmark solveequihash 20:
./src/zcash-cli zcbenchmark solveequihash 20
[
{
“runningtime” : 75.57509600
},
{
“runningtime” : 23.41031000
},
{
“runningtime” : 50.49199300
},
{
“runningtime” : 78.45935600
},
{
“runningtime” : 177.81525600
},
{
“runningtime” : 61.17420500
},
{
“runningtime” : 65.62556100
},
{
“runningtime” : 62.08250400
},
{
“runningtime” : 29.22251500
},
{
“runningtime” : 127.41075500
},
{
“runningtime” : 95.27246100
},
{
“runningtime” : 28.48847700
},
{
“runningtime” : 26.66884400
},
{
“runningtime” : 56.42749700
},
{
“runningtime” : 24.13178700
},
{
“runningtime” : 104.18684000
},
{
“runningtime” : 79.11646800
},
{
“runningtime” : 23.42706600
},
{
“runningtime” : 54.81564200
},
{
“runningtime” : 57.25174500
}
]
I have a dude to calcualate the media because at:
there it says this:
Then calculate the average time of those results (total time / 20) to
get your ‘solve equihash’ time. It’s important to note that there are 2 hashes per solve
the total sums of this amounts of time result: 2544,857011
Please, can anybody say to me if I need to divide per 20 or what?
Thank you very much.